Show how to solve 7/9 times 3/4 with and without cancellation.
Since they are to be multiplied, you could divide the denominator of the first fraction and numerator of the second fraction by 3 to get 7/3 times 1/4. This results in 7/12. If you multiplied first, you'd get 21/36 which would cancel to yield the same fraction (7/12)
without cancellation, it is as follows: 7 3 21 7 --- * --- = ---- = ---- (dividing both Numerator and Denominator by common factor 3) 9 4 36 12
Harkirat can you answer it by writing it? Ill give you a medal.
with cancellation, it is as follows: 7 3 7 1 --- * --- = ---- * ---- (dividing both 3 and 9 by common factor 3) 9 4 3 4 7 = ----- 12
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First for "Without cancellation" 1) First write all the fractions properly side by side with the multiplication signs in-between. 2) Multiply all the numerators together and all the denominators together to get one numerator and one denominator. 3) Now divide both of them by their HCF to get the final result in the lowest form. Now for "With cancellation" 1) First write all the fractions properly side by side with the multiplication signs in-between. 2) Now check if there are certain numbers in numerators which have the same factor as some denominator (need not be its own denominator). If yes, then cancel out these common factors till no common factors are left. 3) Now multiply together all the numerators left and all the denominators left to get one numerator and one denominator.
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