Compute f '(a) algebraically for the given value of a. f(x) = 9x^2 + x; a = 7 Explain please?
so bring the exponent to the base and subtract one from the exponent to get 18x+1. plugging in 7 results in 18(7)+1=127
f'(x) = 18x + 1 f'(a) = 126=1 = 127
does that count as "algebraically"? I never heard that terminology before.
I submitted the answer online and 127 as the form they asked for. Thank you!
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