Ask
your own question, for FREE!

Physics
30 Online

OpenStudy (anonymous):

The upward normal force exerted by the floor is 620N on an elevator passenger who weighs 650 N. How do i find the acceleration The upward normal force exerted by the floor is 620N on an elevator passenger who weighs 650 N. How do i find the acceleration @Physics

Still Need Help?

Join the QuestionCove community and study together with friends!

OpenStudy (anonymous):

The weight of a passenger in an accelerating elevator is \[W = m(g+a)\] so \[a = \frac{W}{m} - g\] in your problem, you should note that \[m = W_0/g\] where \[W_0\] is his normal weight. That means that \[a = \frac{W}{ \frac{W_0}{g} } - g = g( \frac{W}{W_0} - 1) \]

OpenStudy (anonymous):

I should have mentioned that \[W\] denotes the apparent weight in the elevator, in your case 620 Newtons.

OpenStudy (anonymous):

cool using that i got .4523 m/s^2 thanks!

Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!

Join our real-time social learning platform and learn together with your friends!

Latest Questions

gingy57016:
Father Father Father Why never care Father Father Father Why were you never there

3 hours ago
8 Replies
3 Medals

foxey3:
Guys, I'm planning to join my school's talent show. I'm singing an original song

12 hours ago
5 Replies
1 Medal

foxey3:
Guys, I'm planning to join my school's talent show. I'm singing an original song

1 day ago
0 Replies
0 Medals

whyjustwhy:
What is the value of the expression below when y, equals, 2y=2? 4, y, minus, 8 4y

1 day ago
3 Replies
0 Medals

somnium:
y'all it finally let me save my damn screenshot off the Xbox app

4 hours ago
5 Replies
1 Medal