Ask your own question, for FREE!
Physics 10 Online
OpenStudy (anonymous):

The upward normal force exerted by the floor is 620N on an elevator passenger who weighs 650 N. How do i find the acceleration The upward normal force exerted by the floor is 620N on an elevator passenger who weighs 650 N. How do i find the acceleration @Physics

OpenStudy (anonymous):

The weight of a passenger in an accelerating elevator is \[W = m(g+a)\] so \[a = \frac{W}{m} - g\] in your problem, you should note that \[m = W_0/g\] where \[W_0\] is his normal weight. That means that \[a = \frac{W}{ \frac{W_0}{g} } - g = g( \frac{W}{W_0} - 1) \]

OpenStudy (anonymous):

I should have mentioned that \[W\] denotes the apparent weight in the elevator, in your case 620 Newtons.

OpenStudy (anonymous):

cool using that i got .4523 m/s^2 thanks!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Countless7Echos: Ah trying out the whole T.V girl drawing :p (I love drawing eyes)
3 hours ago 11 Replies 6 Medals
kaelynw: starting to draw a hand
3 days ago 16 Replies 2 Medals
Twaylor: Rate it :D (Took 2 days)
3 days ago 7 Replies 0 Medals
XShawtyX: Art, Short Writing Assignment: Imagining Landscapes
1 day ago 7 Replies 1 Medal
XShawtyX: Chemistry, Help ud83dude4fud83cudffe
4 days ago 13 Replies 1 Medal
kaelynw: tried a lil smt, the arm is off but i like the other stuff
4 days ago 27 Replies 3 Medals
kaelynw: art igg
4 days ago 14 Replies 1 Medal
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!