Question

if i am trying to find y and it ends up being 0=0 what do i do? if i am trying to find y and it ends up being 0=0 what do i do? @Mathematics

Answer 1

cry

Answer 2

0=0 is always true so its all solutions

Answer 3

or rather infinite solutions

Answer 4

lol i already did last night.

Answer 5

okay so if i am looking for x y and z and y is 0=0 then its x=5 z=-2 and y=infinite solutions?

Answer 6

or the whole problem is infinite solutions?

Answer 7

dunno, depends on how right you did the math from the original problem

Answer 8

im pretty sure its all right.

Answer 9

whats the original so that I can compare to it?

Answer 10

solve by substitution (x-4y+z=6) (2x+5y-z=7) (2x-y-z=1)

Answer 11

x- 4y+z = 6
2x+5y -z = 7
2x - y -z = 1

2x= 7-5y + z

(7-5y + z) - y -z = 1

7-6y = 1

-6y = -6

y = 1

you sure you did it right?

Answer 12

haha okay i did do it wrong. Thanks lol.

Answer 13

x- 4y+z = 6
2x+5y -z = 7
2x - y -z = 1

x- 4+z = 6
2x+5 -z = 7
2x - 1 -z = 1

lol ... good luck with it ;)

Answer 14

Thanks. :).

Answer 15

okay so i am confused again!!! :(.

Answer 16

lol ... what is it know?

Answer 17

okay so i got y=1 then i got confused...:(. i feel soooooo freaking stupid!

Answer 18

ok, we know y = 1, or at least it has to for this to work out; so lets go ahead and use it:

x- 4+z = 6
2x+5 -z = 7
2x - 1 -z = 1

x+z = 10
2x -z = 2
2x -z = 2

the last 2 equations are the same so we can just use one of them right?


x+z = 10 ; x = 10-z
2x -z = 2

2(10-z)-z=2

20 -2z -z=2

-3z = -18

z = 6

Answer 19

using the first eq; x+z = 10; and z=6, x has to be 4

Answer 20

dbl chk

Answer 21

x- 4y+z = 6
4 1 6
------------
4 - 4 + 6 = 6 , good

2x+5y -z = 7
4 1 6
-------------
8 + 5 - 6 =7; good


2x - y -z = 1
4 1 6
------------
8 - 1 - 6 = 1 ; good

Answer 22

okay now i feel really stupid because that ended up being simple...lol thanks. Again. :).

Answer 23

;)