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OpenStudy (anonymous):

2(x-2)≤-2(1-x)

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OpenStudy (saifoo.khan):

Divide 2 from both sides. \[\frac{2(x-2)}{2} ≤ \frac{-2(1-x)}{2}\] \[x-2 ≤ -2 + x\] \[x - x ≤ -2 + 2\] \[0 ≤ 0 \]

jimthompson5910 (jim_thompson5910):

2(x-2)≤-2(1-x) 2x-4≤-2+2x 2x-2x≤-2+4 0x≤2 0≤2 Since the inequality is always true, there are an infinite number of solutions.

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