Question

2(x-2)≤-2(1-x)

Answer 1

Divide 2 from both sides.

\[\frac{2(x-2)}{2} ≤ \frac{-2(1-x)}{2}\]
\[x-2 ≤ -2 + x\]
\[x - x ≤ -2 + 2\]
\[0 ≤ 0 \]

Answer 2

2(x-2)≤-2(1-x)


2x-4≤-2+2x


2x-2x≤-2+4


0x≤2


0≤2


Since the inequality is always true, there are an infinite number of solutions.