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OpenStudy (anonymous):

how do you find the x and y intercepts to y=(x+1)^2

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OpenStudy (anonymous):

plug in 0 for x and thats the y intercept then plug in 0 for y and thats the x intercept

OpenStudy (anonymous):

you must be in my class or something, that was my homework for tonight!!!

OpenStudy (anonymous):

soccerdoggie6 is right: when x = 0, y =1 so 1 is the y-int or (0,1) when y =0, x+1 =0 or x=-1. so -1 is the x-int or (-1,0)

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