Solve: (n+2)!/(n-1)! = 210
1/(n-1)(n)(n+1)=210
??
\[\frac{(n+2)!}{(n+1)!}=n(n+1)(n+2)\] it is a bit more straight forward when you realise that.
Mr.klinker is 35 and his daughter is 10 , in how many years will mr.klinker be twice as old as his daughter? ~~PLZ HELP
\[\frac{(n+2)!}{(n-1)!}=(n+2)(n+1)(n)\]
can someone wplease explain how to do a problem like this
i i get it i was doing it as plus one but its minus one
so basically you have 3 consecutive integers whose product is 210, which gives n = 5
Mr.klinker is 35 and his daughter is 10 , in how many years will mr.klinker be twice as old as his daughter? ~~PLZ HELP sorry i posted here but wont let me post
Thank you guys! :) I got it now.
thank you satelite73 ! but how would you find the answer
15
years
well for a small number like 210 i would guess and check
35+x=2(10+x) 35+x=20+2x 15=x
thanks!
?? what is this x = 15?
zalxo asked this: Mr.klinker is 35 and his daughter is 10 , in how many years will mr.klinker be twice as old as his daughter? ~~PLZ HELP sorry i posted here but wont let me post
so for my second question George is 7 and his mother is 37. In how manyyears will his mother be 3 times as old as he is. would the answer be 37+x=3(7+x) 37+x=21+2x
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