A cable weighing 0.6 pounds per foot is attached to a small 80-pound robot, and then the robot is lowered into a 40-foot deep well to retrieve a 7 pound wrench. The robot gets out of the well (carrying the wrench) by climbing up the cable with one end of the cable still attached to the robot. How much work does the robot do in climbing to the top of the well? A cable weighing 0.6 pounds per foot is attached to a small 80-pound robot, and then the robot is lowered into a 40-foot deep well to retrieve a 7 pound wrench. The robot gets out of the well (carrying the wrench) by climbing up the cable with one end of the cable still attached to the robot. How much work does the robot do in climbing to the top of the well? @Mathematics

Question

amistre64 · Answer

87*40 + cable weight integrates from 0 to 40

amistre64 · Answer

er perhaps 0 to 20 since it just needs to get up half the cable

amistre64 · Answer

since work = force x distance; the force, cable wise is; weight*length ... but i feel im missing something

amistre64 · Answer

$$\int_{0}^{20}.6x\ dx=.3x^2$$
20^2 = 400

400* .3 = 120.0 for the cable if im recalling it right

amistre64 · Answer

87*40 + 120 = 3480 + 120 = 3600  maybe

anonymous · Answer

$$\int\limits_{0}^{40} (.6x/2) + 87 = 3720$$
Well, that's the answer, but thanks amistre!