Mathematics
OpenStudy (anonymous):

x^2-7x+12=0 solve, completing the square

OpenStudy (saifoo.khan):

3,4

OpenStudy (anonymous):

can u show how?

OpenStudy (saifoo.khan):

(x-4)(x+3)=0

OpenStudy (anonymous):

$x^2-7x+12=0 \Rightarrow (x-4)(x+3)=0 \Rightarrow x =3,4$

OpenStudy (anonymous):

Right answer but not by completing the square: $(x-7/2) ^{2} - 1/4 = 0$ (x-7/2) ^{2} = 1/4 (x-7/2) = sqrt (1/4) = $\pm1/2$ x = 7/2 $\pm$1/2 x = 6/2 = 3 or x = 8/2 = 4

OpenStudy (anonymous):

$\checkmark$