Find the equation of the tangent line to y^3+xy=-2x^2-x+1 going through (-1,1) Find the equation of the tangent line to y^3+xy=-2x^2-x+1 going through (-1,1) @Mathematics

Question

anonymous · Answer

so take the derivative using implicit differentiation and get 
$$3y^2y'+xy'+y=-4x^2-1$$ now you can solve for y' using algebra, or you can just plug in the numbers x = -1 and y = 1 and solve for y' then

anonymous · Answer

typo there it should be 
$$3y^2y'+xy'+y=-4x-1$$