Question

What's Wrong with This Answer?
2 sec, posting the attached img
What's Wrong with This Answer?
2 sec, posting the attached img
@Mathematics

Answer 1

its correct

Answer 2

Technicality error then..

Answer 3

\[y = (\sin3x)^{\ln x}\]
\[\ln y = \ln y \times \ln \sin 3x\]
\[\frac{1}{y}\times \frac{dy}{dx} = \ln \sin 3x \times \frac{1}{y} \times \frac{dy}{dx} \ln y \times \frac{1}{\sin 3x}\times 3\times \cos 3x\]

Answer 4

\[\frac{1}{y}\times \frac{dy}{dx} = \ln \sin 3x \times \frac{1}{y} \times \frac{dy}{dx}+ \ln y \times \frac{1}{\sin 3x}\times 3\times \cos 3x\]

Answer 5

its ln x on right side

Answer 6

Do the algebra on your own!

Answer 7

\[\ln y=(lnx)\ln(\sin3x)\]