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OpenStudy (anonymous):

What's Wrong with This Answer? 2 sec, posting the attached img What's Wrong with This Answer? 2 sec, posting the attached img @Mathematics

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OpenStudy (anonymous):

OpenStudy (anonymous):

its correct

OpenStudy (anonymous):

Technicality error then..

OpenStudy (anonymous):

\[y = (\sin3x)^{\ln x}\] \[\ln y = \ln y \times \ln \sin 3x\] \[\frac{1}{y}\times \frac{dy}{dx} = \ln \sin 3x \times \frac{1}{y} \times \frac{dy}{dx} \ln y \times \frac{1}{\sin 3x}\times 3\times \cos 3x\]

OpenStudy (anonymous):

\[\frac{1}{y}\times \frac{dy}{dx} = \ln \sin 3x \times \frac{1}{y} \times \frac{dy}{dx}+ \ln y \times \frac{1}{\sin 3x}\times 3\times \cos 3x\]

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OpenStudy (anonymous):

its ln x on right side

OpenStudy (anonymous):

Do the algebra on your own!

OpenStudy (anonymous):

\[\ln y=(lnx)\ln(\sin3x)\]

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