If xy + 8e^y = 8e, find the value of y'' at x =0. Attempt: I know what the second, and first derivative will look like. I just don't know how to go about with plugging in the x=0. If xy + 8e^y = 8e, find the value of y'' at x =0. Attempt: I know what the second, and first derivative will look like. I just don't know how to go about with plugging in the x=0. @Mathematics

How am I suppose to solve for x = 0 if I don't even have a function in the first place. Above is not a function right?

implicit differentiation

is that really \[8e\] on the right?

if so you get 3 replying right now... 4 viewing No Medals Yet \[xy'+y+8e^yy'=0\] solve for \[y'\] and then do it again

at x=0 you have from the original equation \[8e^y=8e\] telling you that if x = 0 then y = 1

Do we solve for y' when x = 0?

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