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-7/9c=3/5
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\[c = \frac{27}{35}\]
\[-\frac79c = \frac35\]
I'm sorry, yes the answer is c= 27/35
step by step plz
Cross multiply, \[-7c \times 5 = 3 \times 9\] \[-35c = 27\] \[c = -\frac{27}{35}\]
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basically, in order to solve for the variable, you multiply each side by the reciprocal (the inverse) of the number besides that variable. In this case, multiply -9/7 on each side to get rid of the -7/9. you'll end up with -35c=27. Divide both sides by -35 and you get -27/35
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