derivative problem help please.

yeah what's up?

whats the question

\[d ^{2}x/dt ^{2} \] if dx/dt= 9x sin x

use the product rule

i get that i just don't understand the second derivative of x.

f"(x) = d/dx f'(x)

same procedure

use your first derivative to find the second

the answer would be 9x((cos(x))+9(sin(x)) because of the product rule :)

yes i understand that. what i mean is that when you take the second derivative of x, it should not equal 1 like it would in the first derivative. i don't know how to find that.

f'(x) = 9(sinx+xcosx) use that and find it's derivative to find f"(x) for reference: f"(x) = 18cos(x)-9xsin(x)

the way you wrote the problem you will have to take the derivative implicitly, treating x as a function of t

use your first derivative to find the second

watch your signs its - not +

so how do i take the derivative implicitly?

have you done implicit differentiation?

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