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OpenStudy (anonymous):
A signal flare is fired upward with initial speed 245 m/s. A stationary balloonist at a height of 1960 m sees the flare pass on the way up. How long after this will the flare pass the balloonist again on the way down?
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OpenStudy (anonymous):
s=ut+1/2 at^2 1960=245t-4.9t^2 Rearrange to get a quadratic for t: t=10 or 40
OpenStudy (anonymous):
The first sighting is at 10 seconds so the second (when it comes back down) is 30 seconds thereafter.
OpenStudy (anonymous):
Thanks!!
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