Question

how do i solve :


G= (x2-8x+16) how do i solve :


G= (x2-8x+16) @Mathematics

Answer 1

is that supposed to be x squared
(x-4)^2

Answer 2

yes it is

Answer 3

\[G=x{^2}-8x+16\]
Correct?

Answer 4

yes

Answer 5

x^2 - 8x + 16
x^2 - 4x - 4x + 16
x(x - 4) -4(x - 4)
(x - 4)(x - 4)

so
G = (x - 4)(x - 4)

Answer 6

Thank you ! :)

but then how did i get (x-7) and (x-1) ?

Answer 7

Maybe you factorised it wrong....☺

If u send the full solution that you made, I can tell u where u went wrong.....

Answer 8

:) thankss agaain !

G= (x^-8x+16)
= (x-4)-9
= (x-4-3) (x-4+3)
= (x-7) (x-1)

Answer 9

How did u get (x -4)-9 in the second step ??? .....this is wrong !!!
what is yr logic for that?? pls explain in words..

Answer 10

:P !! aha well this is how my "teacher" solved it !

Answer 11

it is wrong !!!
Is the "teacher" your school teacher or some personal tutor or some online teacher ???

Answer 12

NO ! schooool teacher imagine that !

Answer 13

are u frm USA ???

Answer 14

:P no im lebanese

Answer 15

and yourself ? :)

Answer 16

I am an Indian..☺

Answer 17

coool !my mom is indian too ! :)

Answer 18

Really !!!! What's her name n what part of India is she from???

Answer 19

She`s canadian indian :P

Answer 20

and do you mind telling me where i went wrong in the math question :P

Answer 21

i have a test coming up soon and im struggling alot with this subject

Answer 22

do u hv a SKYPE account??

Answer 23

mmm nope why :P ?

Answer 24

Because on SKYPE we can have live voice chat and also share a whiteboard and explaining will be faster and better

Answer 25

that`st true , but i would just like to discuss it with my parents if they are ok with it

Answer 26

will that take time??

Answer 27

yup

Answer 28

ok I will try to explain here......

Answer 29

cool , try your best if you don`t mind and i appreciate your help alot , thanks !

Answer 30

This is a quadratic equation.......its general form is
ax^2 + bx + c where a=coefficient of x^2 term , b=coefficient of x term and c=constant
So first we put the given equation in general form
x^2 + (- 8)x + 16, so here a = 1, b= -8 and c = 16
Now we find the product a*c = 1*16 = 16
Then we have to find two factors of 16, say P and Q, so that P*Q=a*c and P+Q=b

Is it clear till now???

Answer 31

yes it is :) thank you very much !

Answer 32

Ok, now we can factorise 16 as
16 = 1 * 16 or -1 * -16
= 2 * 8 or -2 * -8
= 4 * 4 or -4 * -4
= 8 * 2 or -8 * -2
= 16 * 1 or -16 * -1 (notice that the last two factors are same combination as first two !!!

Out of these combinations we find that only one combination fulfills both the requirements
"Then we have to find two factors of 16, say P and Q, so that P*Q=a*c and P+Q=b"
-4 * -4 = 16 (a*c) and (-4) + (-4) = -8 (b)
so we split the middle term bx as follows : -8x = -4x - 4x
x^2 - 8x + 16
x^2 - 4x - 4x + 16
Now we take out the common factor of the first two terms and then of the last two terms as follows to get:
x(x - 4) -4(x - 4)
(x - 4)(x - 4)

this way we have factorised.........

Answer 33

WOOOOOOOOOOOOOOOW ! that`s amazing !
thank you soooooooo muchh ! you helped me alot my friend :) i do appreciate it alot , 2morow ill be online the same time or earlier , maybe we can talk tomorow , i have to sleeep now , so takecare and goodnight !

Answer 34

best of luck and Good Night !!!

Answer 35

thanks youu too night !