Question

The length of a rectangle exceeds twice the width by 4 feet. If the width is doubled and the lenghth is diminished by 2 feet, a new rectangle is formed whose perimeter is 8 feet more than the perimeter of the original rectangle. Find the dimensions of the original rectangle. Use a let statement. The length of a rectangle exceeds twice the width by 4 feet. If the width is doubled and the lenghth is diminished by 2 feet, a new rectangle is formed whose perimeter is 8 feet more than the perimeter of the original rectangle. Find the dimensions of the original rectangle. Use a let statement. @Mathematics

Answer 1

Let L be the length of the original rectangle and W be the width of the original rectangle. Based on the first sentence, what is the relationship between L and W?

Answer 2

no let statement like let x= the width and let like whatever it is =- the lenghth

Answer 3

It does not matter what variable names you use. L and W will do. Stick with me to help you figure out the answer and learn how to solve such problems.

Answer 4

your wrong.. this is my hw i think i would know

Answer 5

ı don't undernstand :)

Answer 6

Ok.

Answer 7

your question

Answer 8

@VeryShy - You don't understand my question about relationship between L and W based on first sentence of the stated problem?

Answer 9

lenght=8 witd=1 ?

Answer 10

First sentence simply says L exceeds twice width by 4. That means L = 2W + 4. I have not even gotten to other parts of the problem before @xokatexo interrupted insisting on sticking to his homework.