Question

PLZ HELP!!!!
A launched rocket has an altitude, in meters, given by the polynomial h+vt-4.9t^2, where h is the height, in meters, from which the launch occurs, at velocity v in meters per second, and t is the number of seconds for which the rocket is airborne. If a rocket is launched from the top of a tower 50 meters high with an initial upward speed of 30 meters per second, what will its height be after 2 seconds?

h+vt-4.9t^2
Where h = 50
v = 30
t = 2

50+30*2-4.9*2^2
whats the answer?

Answer 1

You need a calculator?

Answer 2

lol i have one smarty pants

Answer 3

50+30*2-4.9*2^2=90.5
there's nothing else to do but use it

Answer 4

well its saying 90.5 is wrong

Answer 5

Why does one need a calculator for this computation?
50 + 60 - 4.9 * 4 = 110 - 19.6 = 90.4

Answer 6

THX GT