Question

2x^2-7x+3=0 completeing the square im using the quadratic formula but i keep getting - sqare root so do i use imaginary numbers?

Answer 1

the discriminant is\[b^2-4ac=(-7)^2-4(2)(3)=25>0 \]so you have made a mistake somewhere.

Answer 2

There for making it -7i+_\[-7i \pm \sqrt{73}\]/4

Answer 3

All over 4?

Answer 4

show your work, you have made a mistake somewhere...

Answer 5

\[2x^2-7x+3=0\]\[a=2\]\[b=-7\]\[c=3\]\[x={-b \pm \sqrt{b^2-4ac} \over 2a}\]plug in the numbers and tell me what you get.

Answer 6

Same answer.

Answer 7

-73