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Charlie, who is 4 feet tall, walks away from a streetlight that is 16 feet high at a rate of 4 feet per second, as shown in the figure. Express the length s of Charlie's shadow as a function of time. (Hint: First use similar triangles to express s as a function of the distance d from the streetlight to Charlie.)
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s(t)=t s(t)=4/3t s(t)=5t s(t)=4t s(t)=6t are the answers
ok the answer is s(t)=4/3t ...could someone explain why though? i kinda guessed.
i can draw out the pic they have too if u want...
|dw:1319768017684:dw|
i tend to use w for distance walked
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by "similar triangles " \[\frac{s}{4}=\frac{s+d}{16}\]
|dw:1319681627423:dw|
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