g(x)= 4x^-5, h(x)= (x+2)/4 what is g(x)/h(x), please she work/explain g(x)= 4x^-5, h(x)= (x+2)/4 what is g(x)/h(x), please she work/explain @Mathematics
i need it as if it still had X in the equation
g(x)= 4x^-5, h(x)= (x+2)/4 try to divide the g/h
well, 1st off, if you take the negative exponent and make it a positive by making it a detonator, does the 4 go with it?
where does the 16 come from?
the 4 in the denominator will be mult by the numerator 4
ok, so if we do go with that, then the type of answer im looking for is something like 16(1/x^6+2)
no, because what did you do to get rid of the negative?
the x^-5 wil be mult by the denominator when you changed to positive sign
i was taught that it moves to the detonator
yes look at my solution now,,it goes to the denom and becomes positive on sign
4x^-5, h(x)= (x+2)/4 =16/[x^5(x+2)]=16/[(x^6 +2x^5)] ans
the 16 remains on the numerator and the x^5 now in the denom
but theres only one x^-5 and one x as demonators, so how are there a total of 11 in the end?
note on the sign of16(x^-5)/(x+2)
16(x^-5)/(x+2) =16/[x^+5)(x+2)]
ohhh, you took that as a minus!!! its a negative
now you can mult the denominator
yes im sory i didnot noticed the negative sign before, now its like this 16(x^-5)/(x+2) =16/[x^+5)(x+2)] =16/[(x^6 +2x^5)] ans
did you get it jiwani?
????
tell me if you get confused for i will explain it
aroub may explain it better than me,....lol
haaha!! no its all yours man!! =D
i have a test over this stuff in a few hours so i dont know how much of it my teacher will explain to me, if any at all. but idk, im just gonna ask her and see if she can explain it
ok thnx aroub, i gotta go now,,,lol
ok aroub its your turn
hm jiwani believed me my solution there is correct,,try to se what happened to x^-5 went down to the denom. and changed to x^5
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