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OpenStudy (anonymous):
(e^x-xintoe^x)/e^2x
OpenStudy (lalaly):
using the product rule
\[\frac{d}{dx}xe^{-x} = e^{-x}-xe^{-x} = \frac{1}{e^x}- \frac{x}{e^x}\]
OpenStudy (anonymous):
qutotient rule
OpenStudy (anonymous):
|dw:1319790457983:dw|
OpenStudy (lalaly):
i used the product rule,
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OpenStudy (anonymous):
that is not what I got, I got 1-x/e^x is the derivative
OpenStudy (lalaly):
well thats the same as my answer
OpenStudy (lalaly):
\[\frac{1}{e^x}-\frac{x}{e^x} = \frac{1-x}{e^x}\]
OpenStudy (anonymous):
right lalaly you are right you just didn't eliminate the common term
OpenStudy (lalaly):
what common term? i dont have to eliminate anything
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OpenStudy (lalaly):
its exactly the same since they have a common denomiantor
OpenStudy (anonymous):
e^x over e^x2 simplifies to your 2nd answer of 1-x/e^x
OpenStudy (lalaly):
sumbul used the quotient rule
i used the product rule
so my answer was simplified from the beginning i did not get e^2x.... i did it a different way...so u can have to methods of doing it