Question

A rectangular garden has a width that is 8 feet less than twice the length. Fine the dimensions if the perimeter is 20 feet.

Answer 1

For such problems, you should assign variable names to unknown quantities. Here, width and length are. So, call them W and L.

Now, use the information given to write equations in terms of W and L and solve. There are two pieces of information given, which will result in two equations in two variables. You should be able to solve them.

Answer 2

Width is 8 feet less than twice the length.
W = ?

Answer 3

8<2X

Answer 4

IS THAT RIGHT

Answer 5

W is the width. It is 8 less than twice the length. Twice the length is 2L. Width is 8 less (means you need to subtract 8 from 2L).

So, W = 2L - 8. That is the first equation.

Answer 6

Second equation comes from the perimeter information given. Perimeter equals twice the length plus twice the width. So, 2W + 2L = 20. That is the second equation.

Now, you should solve the two.

Answer 7

TO BE HONEST I DO CANT SOLVE IT

Answer 8

DO U SUBSTITUTE THE W WITH THE 8

Answer 9

W = 2L - 8 (equation 1)
2W + 2L = 20 (equation 2)

So, you substitute W from equation 1 into equation 2.
2(2L - 8) + 2L = 20
4L - 16 + 2L = 20
6L = 36
L = 6

Now, plugging this value of L in the first equation, you get:
W = 2*6 - 8
=> W = 4

Answer 10

THANKS GT