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@ ..if 12.5 cu reacts with excess cl gas then 25.4g of cu(ii)cl are produced..find the theoretical and percentage yield
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cu + cl2 = cucl2 63.55 + 2* 35.45 = 134.45 - taking relative atomic masses 12.5 g theoretically produces ( 134.45 / 63.55 ) * 12.5 = 26.446 g persentage yield = (25.4 /26.446) * 100 = 96.1 % to 1 dec place
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