Question

Solve by taking the a logarithm of both sides.

8^x = 23

Answer 1

taking log on both sides we get
xlog8=log23
x=log23/log8
x=1.50785

Answer 2

no sumbul...you cant use log_10 without change base value! You could do what you did if you toke the log_8

Answer 3

ok

Answer 4

take ln then?

Answer 5

we need to make

log_c a
log_b(a) = ---------
log_c b

Answer 6

all right

Answer 7

@sumbul that's the same thing I did when I solved it.

Answer 8

we may rewrite:
2^3x=23

taking log_2 on both sides:

3x= log_2 23

log_2 23 = (log_10 23) / (log_10 2) = 4,52

so 3x = 4.5235

x = 1.5078

Answer 9

answers are same

Answer 10

im was thinking about.. i was wrong when i said "no sumbul...you cant use log_10 without change base value! You could do what you did if you toke the log_8"

We can use
log_c a^b = b log_c a !!

Sorry @sumbul =)