Question

can you please show me how to solve
x^3-6x^2=16x-96

Answer 1

First bring everything over to the same side of the =. This will make 16 become a negtive and 96 a positive.
x^3 - 6x^2-16X+96

Answer 2

Then treat them as 2 different equation soo
(x^3 - 6x^2) and (-16x+96)

Answer 3

Then simplfy each:
(x^3 - 6x^2) = x^2(x - 6)
and
(-16x+96) = -16(x-6)
So your answer is (x-6) & (X^2-16)

Answer 4

Then simplfy them so
(x-6) becomes x-6=0
Bring the 6 over
x=6

And

(x^2-16)=0
x^2=16
\[\sqrt{x}=\sqrt{16}\]
x=4

Answer 5

youre just missing one more solution. instead of taking the x^2-16=0 and solving, you could have factored even further:\[x^2-16=0\iff (x-4)(x+4)=0\iff x=4,x=-4\]so overall you should have x= 6, 4, -4 as solutions.