Question

how do you solve this: log(x+1) = log(2)- log(4x-1)

Answer 1

\[\log(x-1) = \log \frac{2}{4x-1}\]

x-1 = 2/(4x-1)

Solve for x.

Answer 2

Probably add log ( 4x - 1) to both sides to obtain:

log(x+1) + log(4x-1) = log(2)

now use the product rule for logs to obtain:

log( (x+1)(4x-1) ) = log(2)

Assuming the bases of the logs are the same of course. Now you just solve the quadratic equation:

(x+1)(4x-1) = 2

Which you can do by expanding, collecting terms, and factoring again. :)

Answer 3

sorry I misread the plus with the minus up there, but it still works ;) bye o/