Question

Find lim x->infinity of a^x (where a is in (-infinity,-1] )Find lim x->infinity of a^x (where a is in (-infinity,-1] )@Mathematics

Answer 1

so a is negative is what i understand
basically a<0

Answer 2

yes pretty much

Answer 3

like you think above the signs are going to switch an infinity amount of times right as the numbers get bigger and bigger

Answer 4

and also there are going to be some values of x that a^x does not exist for

Answer 5

the limit does not exist

Answer 6

lol i should read what i type before i press enter
but i think i got my point across okay

Answer 7

im not sure what you mean by the signs
will switch an infinity amount of times?

Answer 8

for example
\[(-3)^{141241412}=positive, (-3)^{141241413}=negative\]

Answer 9

but there where also be values of x between such integers such that a^x does not exist

Answer 10

will also be*

Answer 11

if a is -infinity it wont exist?

Answer 12

i don't understand the question
(-3)^even integer=positive
(-3)^odd integer=negative
there will be numbers between integers such that you get a complex number(not real)
the limit does not exist

Answer 13

i'm just saying a is -3 because i thought it would be easy for you to look at a number in the interval given
it doesn't matter what i let a equal in that interval
the limit does not exist

Answer 14

ok thanks