Question

A toy company is performing an experiment to estimate the Roddenberry module of
their new toy car. The car takes a time T to travel around a circular track, and the
Roddenberry module R can be computed as R = (pi/96)T^2.

(a) A lap around the track is clocked at T = 6.2s. Calculate R, and make sure to
indicate the units.
A toy company is performing an experiment to estimate the Roddenberry module of
their new toy car. The car takes a time T to travel around a circular track, and the
Roddenberry module R can be computed as R = (pi/96)T^2.

(a) A lap around the track is clocked at T = 6.2s. Calculate R, and make sure to
indicate the units.
@Mathematics

Answer 1

b) The time T is measured using a digital timer which is accurate to within 0.1s.
What is the maximum relative error in T? Use a linear approximation to estimate
the absolute error in R. When reporting your estimate of R, how many decimal
places should you realistically include?

(c) We need to obtain the value of R with an error of at most 2%. Is this experi-
ment going to be enough, or do we need to buy a more precise (and hence more
expensive) timer?

(d) Now assume we are using a very sophisticated timer that allows us to measure T
with very high precision, so that we can ignore the error it introduces. We still
need the value of R with an error of at most 2%. Can we use 3.14 instead of in
our calculation? Should we use 3:1416 instead? 3:14159265? Something else?

....its kinda long ><

Answer 2

the error of R , we can use delta R

Answer 3

dR = 2(pi/96)T*dT

Answer 4

when T = 6.2 s we have R = 1.2579

Answer 5

so dR = .4057 dT, so dT = +-.1 s ,
dr = .4057 (+-0.1) = + - .04

Answer 6

delta R ~ dR = +-.04

Answer 7

how do you do the last part, d)

Answer 8

i dunno ><

Answer 9

teach me plz