Question

Integral 1 / ( y√(3+(y^2)))

Answer 1

3 + y^2 = t use this substitution

Answer 2

hmm or try this 3 + y^2 = t^2

Answer 3

2y = 2t*dt/dy
dy = t/y*dt

Answer 4

t
---- dt
y*y*(t)


\[\frac{1}{y^2}dt\]
y^2 = t^2 - 3
\[\frac{1}{t^2 -3}dt\]
you can do it now

Answer 5

thanks