How do you factor completely: 12x^-6y^-3z^4 + 8x^-3y^-2z^-1 - 6x^3y^2z^-3 +10

Question

anonymous · Answer

incorrect expression ..

anonymous · Answer

What do you mean it's incorrect?

turingtest · Answer

8x^-3y^-2z^-1 should be written as (8x^-3)(y^-2)(z^-1) or better yet try the equation feature:$$8x^{-3}y^{-2}z^{-1}$$but even with that I don't see how to factor $$12x^{-6}y^{-3}z^4 + 8x^{-3}y^{-2}z^{-1} - 6x^3y^2z^{-3} +10$$ try Wolfram...

anonymous · Answer

What or who is Wolfram?

turingtest · Answer

Wolfram Alpha is a site that will factor and integrate things for you. Try to enter your expression (you will need to add parentheses on the exponents first) into http://www.wolframalpha.com/

turingtest · Answer

and write the word "factor" before it.

anonymous · Answer

Something like this $$ 2x^{-6}y^{-3}z^4 + 8x^{-3}y^{-2}z^{-1} - 6x^3y^2z^{-3} +10 = -\frac{2 \left(3 x^9 y^5-4 x^3 y z^2-5 x^6 y^3 z^3-z^7\right)}{x^6 y^3 z^3} $$

anonymous · Answer

So basically the only common factor you can pull out is the "2"?

anonymous · Answer

yes.

anonymous · Answer

Is it necessary to find a common denominator for a factoring problem?

turingtest · Answer

That and you need to recognize that the denominator will be composed if the negative exponents LCM. http://www.wolframalpha.com/input/?i=factor+12x%5E%28-6%29y%5E%28-3%29z%5E4+%2B+8x%5E%28-3%29y%5E%28-2%29z%5E%28-1

anonymous · Answer

No,but it's a good practice

turingtest · Answer

composed OF^

anonymous · Answer

Thanks guys