A bicycle wheel with radius 26" rotates through an arc that measures 80°. What is the length of the arc of the tire that touched the ground?

= ? PI inches

Question

A bicycle wheel with radius 26" rotates through an arc that measures 80°. What is the length of the arc of the tire that touched the ground?

= ? PI inches

jamesj · Answer

If the wheel did a complete rotation--360 degrees--the arc length would 2pi.r = 2.pi.26 = 52.pi.

Hence, having moved through just x degrees, the arc length is

$$ \frac{x}{360} . 2\pi r $$

jamesj · Answer

In this case x = 80 and you also know r = 26 inches.  Now solve.

anonymous · Answer

so what i do now like whats the answer lol sorry im in a rush?

jamesj · Answer

C'mon.  Don't be so lazy. 

If x = 80, and r = 26, then

Arc length = (x/360) . 2pi.r = (80/360).2pi(26) = ....

anonymous · Answer

still dont get it not being lazy but in a huge retricerush lol

hrhsbull · Answer

80/360*2*26pi = 11.56pi