Question

3rd root of 324^11, simplifi
ed plox

Answer 1

first write 324 as a product of its prime factors, so you get:\[324=2^{2}*3^{4}\]so now you have:\[\sqrt[3]{324^{11}}=\sqrt[3]{(2^{2}*3^{4})^{11}}=\sqrt[3]{2^{22}*3^{44}}=\sqrt[3]{2^{21}*2*3^{42}*3^{2}}=2^{7}*3^{14}*\sqrt[3]{2*3^{2}}\]\[\sqrt[3]{324^{11}}=612220032*2^{1/3}*3^{2/3}\]

Answer 2

Ooops, the actual question is : Multiply then Simplify: