Question

Find the vertical asymptotes, if any, for the following function. Please show all of your work.
f(x) = x+11/x^2-16x

Answer 1

x^2 - 16x = 0

Answer 2

the denominator cannot be zero


if it were, then


x^2-16x = 0


x(x-16) = 0


x=0 or x-16=0


x=0 or x=16


So the values x=0 or x=16 cause a division by zero error


So the vertical asymptotes are x=0 and x=16

Answer 3

james I have a question..after your done with this one..can you come back to my question?
thank you

Answer 4

never mind..thank you for helping me with those questions

Answer 5

i can help you. which question do i go bck to?

Answer 6

Thank you Jamesm!!