five sqre root of y minus six = 5

Question

anonymous · Answer

Is it: $$\sqrt[5]{y-6}=5$$

anonymous · Answer

yeah

anonymous · Answer

how do you get that fomat of type?

anonymous · Answer

If so, then bring the $$\sqrt[5]{?}$$ over to the other side of the equals sign, so you have:
y-6=5^5. Then you bring the six over to the other side to make:
y=(5^5)+6
So, y= 3125+6 = 3131.

anonymous · Answer

Click on equation just below where you type.

anonymous · Answer

I'm confused

anonymous · Answer

I get that you have to take the 5 squre root to the other side, and I get that you have to bring the six over, but I'm confused after that.

anonymous · Answer

How are you confused? That's all you need to do.

anonymous · Answer

Do you put a negative in front of the square root  because you are switching sides?

anonymous · Answer

I also don't understand how the y= 3125 + 6 = 3131

anonymous · Answer

No, the square root sign changes to a square sign. For example, $$\sqrt[5]{x}$$ changes to $$x^{5}$$

anonymous · Answer

Because 5x5x5x5x5=3125, then you add the six on to it to get y.

anonymous · Answer

So when you change sides with a square root ( y square root x) you take x and times it by the power of y?

anonymous · Answer

Basically, If you had $$\sqrt[5]{6+y}=3$$ then the $$\sqrt[5]{6+y}$$ would change to a $$3^{2}$$ when it moves from the left hand side of the equals sign to the right hand side. Do you get it now?

anonymous · Answer

Sorry, I mean $$3^{5} $$

anonymous · Answer

no.

anonymous · Answer

XD Basically, what you said was correct.

anonymous · Answer

Wait, but if you have 5 squre root of 6+y = 3, then you would do 6 to the power of 5 then do y to the power of 5?

anonymous · Answer

No, because your moving the power of 5 to the other side of the equation. So you'll have a 3 to the power of 5.