f(x)=2abs(x-40) g(x)=(1/2)x+40 when x is less than 40 and 60 when x is equal or greater than40 Find the derivative of f(g(x)) at x=70 @Calculus1
Can i explain you the question?
Are they on?
Oh ok
Thanks
Hw do u delete
Click your name
i think i understand the questiona
Wait nut I gotta explain it
you have to find the composite function (it will be piecewise) then take the derivative then evaluate
Really g(x) was a graph and I guessed the equation
It was an equation of a line (1/2)x+40 until x = 40 and then at x =40 there was a corner and it became a straight line so I guessed that this was the equation
\[f(x) = 2|x-40| = \left\{\begin{array}{rcc} 80-2x& \text{if} & x < 40\\ 2x -80 & \text{if} & x \geq 40 \end{array} \right. \]
What I am totally confused
I need f(g(x))
i am getting to that. it is complicated by the fact that you have two piecewise functions that you have to find the composition of. that is the hard part
Well f(x) is peicewise?
absolute value is called peice wise?
yes it is defined piecewise. for example \[|x| = \left\{\begin{array}{rcc} -x & \text{if} & x <0 \\ x& \text{if} & x \geq 0 \end{array} \right.\]
Oh cool way of looking at it
that is why taking the derivative is a pain. you have to know what interval you are talking about. the function is piecewise and so is its derivativfe
so that explains why i broke up the original function into two parts. now we can find the composition
Well I don't treat an absolute value as a peicewise I think of it like this \[abs(x)=\sqrt{x ^{2}}\]
but now we are almost home free, because you want the derivative at x = 70, and you said \[g(70)=60\] right?
If the equation has a corner then that means it is peicewise?
Cuz they gave me the graph and I kind of guessed that it was a peicewise function
well usually if you have a functions whose picture is not a smooth curve, you have to define it two different ways at least. if you want an equation that it. if you have something that looks like |dw:1320545222757:dw|
you will not be able to write it as one equation
ok I will draw the function
ok but it doesn't matter that much because the derivative of your function will be one of two constants. it will either be 2 or -2 depending on the values of x
|dw:1320545280585:dw|
Join our real-time social learning platform and learn together with your friends!