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Mathematics 22 Online
OpenStudy (anonymous):

Determine whether {(1,0,1,0),(1,1,0,0), (1,1,1,1), (0,0,0,1)} is a basis for R^4

OpenStudy (zarkon):

it is

OpenStudy (anonymous):

Yes, the book says that it is, but it does not offer an explanation for why. I'm trying to prove its linear independent and that it spans , but i dont know how to make it look like a proof

OpenStudy (zarkon):

make a matrix ...either row reduce it or find the determinant

OpenStudy (anonymous):

what do i want the matrix to look like? is it just reduced row with all zeros on the right side?

OpenStudy (zarkon):

put the 4 vectors above in a matrix...put it into rref and you will get the identity matrix.

OpenStudy (anonymous):

ok i did that and that proves linear independence, Thanks! I can see how that comes out, but now can you help me show the span?

OpenStudy (zarkon):

you have 4 vectors that are L.I. therefore they span a subspace of dimension 4...hence they span all of R^4

OpenStudy (anonymous):

oh by definition of a span?

OpenStudy (zarkon):

you can also do this let A be the above vectors in a matrix then t be any vector in R^4 since Det(A) is not zero it is invertable thus there is a vector \[v\in\mathbb{R}^4\] such that \[Av=t\] namely \[v=A^{-1}t\]

OpenStudy (anonymous):

what about something like -> A(1,0,0,0)+B(0,1,0,0)+C(0,0,1,0)+D(0,0,0,1). That then shows that it spans R4 after we have the linear independence proven by the matrix

OpenStudy (zarkon):

you would have to set that equal to some arbitrary vector in R^4 and show that a solution exists

OpenStudy (zarkon):

there is a theorem that says that if Dim(V)=n and S={v_1,...v_n} is a set in L.I. vectors then S spans all of V

OpenStudy (anonymous):

then i could just use that theorem i think.

OpenStudy (zarkon):

it should be somewhere in your book.

OpenStudy (zarkon):

what book are you using?

OpenStudy (anonymous):

robert messer linear algebra gateway to mathematics its a terrible book, its written as if its just a mere explanation to someone who already has a phd in this stuff. very little detail

OpenStudy (zarkon):

I have many linear algebra books, but I don't have that one

OpenStudy (anonymous):

but 3.15 states that is V is n dimensial , if v1 to vn pans v then it is l.i. and if its l.i then it spans v.

OpenStudy (zarkon):

that's it

OpenStudy (anonymous):

I attend MSU and they have this book only because the person that wrote it, graduated from here.

OpenStudy (zarkon):

ic

OpenStudy (anonymous):

I normally have no problem learning from these textbooks but i really think this one is a poor read, but i have a small quiz at 2pm today on basis and dimension.

OpenStudy (zarkon):

ic...good luck

OpenStudy (anonymous):

if you dont mind me asking, how often are you on this thing, you've been very helpful.

OpenStudy (zarkon):

I on fairly often...but the time is not consistent.

OpenStudy (zarkon):

I usually have it running in the background when I'm in my office

OpenStudy (anonymous):

a math professor of some sort?

OpenStudy (zarkon):

yes

OpenStudy (zarkon):

Ph.D. Mathematical Statistics

OpenStudy (anonymous):

thats respect, im a mathematics major, i hope to do something analytically for a career, but to have continued on to get a PhD I dont think I could handle it, thanks again! Hopefully you will be around for more of my questions. Very few people here can articulate linear algebra so well.

OpenStudy (zarkon):

cool...and good luck again on your quiz

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