Question

Simplify and show work please!
^3sqrt. 4x^3y^5 times ^3sqrt. 12y^2
Thanks Simplify and show work please!
^3sqrt. 4x^3y^5 times ^3sqrt. 12y^2
Thanks @Mathematics

Answer 1

Can you please explain your notation?

Answer 2

\[\sqrt[3]{4x^3y^5}\times \sqrt[3]{12y^2}\]

Answer 3

Yayyy! [:

Answer 4

idk if this steps are right.
^3sqrt. x^3y^3 times ^3sqrt. 4y^2 times ^3 sqrt. 12y^2

Answer 5

since you have to isolate for x or y, you decide which first and use the one you didnt isolate inside of the equation to later evaluate. Since you wrote all that, I dont quite get the steps you did....

Answer 6

okay. I hope the server is back.\[\sqrt[3]{x^3y^3y^3}\times \sqrt[3]{4y}\times \sqrt[3]{12}\]

Answer 7

I know the answer is\[2xy^2\sqrt[3]{6y}\] but how do you get that?

Answer 8

How did you do it and do not know how you got there? lol

Answer 9

I separated all the ^3 from the numbers/variables that couldnt be ^3.
So\[\sqrt[3]{x^3y^3y^3}\] are separated from\[\sqrt[3]{4y} \times \sqrt[3]{12}\] and so from that info the answer is :\[2xy^2\sqrt[3]{6y}\] does it make sense or no?