Question

Radical equations, simple but im stuck with the signs! do you get rid of the negative when you square??

Answer 1

\[\sqrt{6x+1}+3=0\]

Answer 2

yeah

Answer 3

The solution is complex

Answer 4

i got 10/6

Answer 5

something is wrong then.

Answer 6

:D thanks, can someone solve it so i can see if i got the right answer

Answer 7

\[\sqrt{11} + 3 \neq 0\]

Answer 8

i think its 9/6? does that sound right

Answer 9

There is no real number that you can plug that has a negative square root, you need that \[\sqrt{somenumber} = -3\]

Answer 10

are you agree?

Answer 11

I'm sorry but I'm confused

Answer 12

Well the step in wich you square it's wrong, for example:
\[2\neq -2\]
but \[(2)^2 = (-2)^2\]

Answer 13

Answer is NO SOLUTION.

Answer 14

Are you 100% sure?

Answer 15

200%

Answer 16

ok thank you, brb

Answer 17

There is a solution, but its a complex solution.

Answer 18

Prove it @victor.

Answer 19

what do you want as a proof?

Answer 20

if you multiply a negative by a negative its positive....do you rmbr that stuff?