Question

Find the zeros of the function f(x)=2x^2-16x+32 by factoring.

Answer 1

Set f(x) = 0:
2x^2-16x+32 = 0
2(x^2-8x+16) = 0
x^2-8x + 16 = 0
x^2-4x-4x+16 = 0
x(x-4)-4(x-4) = 0
(x-4)(x-4) = 0
(x-4)^2 = 0
x - 4 =0
x = 4

Answer 2

Thanks for writing out how you did it...

it really helps

Answer 3

You're most welcome

Answer 4

Appreciate you Sheg