Question

My homework probem is 4^(3x-3)=32. I know that I can put 4 as 2^2 and multiply the 2 (exponent) to (3x-3) but then what do I do with the 32?

Answer 1

\[4^{3x-3}=32\] that is what the problem looks like

Answer 2

you see that 4
\[4=2^2\] so
\[4^{3x-3}=2^{6x-6}\] and also
\[32=2^5\] so you get
\[2^{6x-6}=2^5\]
and then solve
\[6x-6=5\]

Answer 3

ohhh so both of the twos are cancelled then?

Answer 4

it is not "canceled"
it is a fact that
\[b^x=b^y\iff x=y\]

Answer 5

thank you! I really appreciate it!