Question

Use Newton's Method to find the solution of x^3-7x-4=0 correst to six decimal places. Let starting value x0=3. (Please tell me what to do on calculator, thanks)

Answer 1

i might be thinking of another method of newton lol

Answer 2

oh yea, thats all i could find online too, lol.

Answer 3

http://upload.wikimedia.org/wikipedia/en/math/3/5/b/35b501243f57758c02dd9b0ce68b809a.png

Answer 4

hmm i just have to remember how you do it on a calculator i know you have to store values and stuff give me a sec to look it back up

Answer 5

thanks, i'm familiar of that, but I'm just not sure how its supposed to be done on a calculator :(

Answer 6

http://www.tc3.edu/instruct/sbrown/ti83/newton.htm

Answer 7

that would be the way without using a table... this video below i would assume is what your teacher will give http://www.youtube.com/watch?v=k4x0H0kM2Wo

Answer 8

Lol, i also found the first one, but reading it just made me more messed up. The youtube video seem s to make a little more sense, thanks.

Answer 9

do you know how to store values... or use the ->

Answer 10

does it have anything to do with the [Ans] key?

Answer 11

nope above the on key there is a button that says sto>

Answer 12

so basically what you'd do for your problem would be

Answer 13

uh, yea, i kinda have to use my imagination cuz i think someone stole my calculator at school today. so i have nothing to work with...

Answer 14

Y1=x^3-7x-4
Y2=3x^2-7

then push x, sto->, 3 which will make 3 be stored in the variable x... so whenever you type x in, it will use the integer 3

Answer 15

so the next thing you'd do is use the newtons equation \[x_ 1=x_ 0-\frac{f(x_ 0)}{f'(x_ 0)}\]

Answer 16

well when you put you put equations into the y= (place where you put your equations for graphing), it stores them as \[y_ n\] so that if you want to use them algebraically you can just type in \[y_ 1+y_ 2\]

Answer 17

so far so good?

Answer 18

alright, so f(x) was y1 correct and f'(x) was y2 and you stored x as 3 in your calculator.

Answer 19

i think i kinda get it. i just wish i had a better math prof to actually explain it in class

Answer 20

well i'll finish it up .... so since y1=*a function with x in it... it will automatically put in 3 to create f(x0)

so what essentially the calculator is doing is taking the number 3 and solving your y1 and y2 for that number

lastly you just simply use the formula

to get x-(y1*your equation at x0*/y2*your derivative at x0*, store as x.. so it will compute it and store the newly answer as x... pushing enter again will use the same formula above and store it as x again... then you just do it until you get to the specified error

Answer 21

thanks for taking the time to help me out. i need to review all this stuff now, lol.