Describe the graphs of the functions f(x) = 2^x – 3 and g(x) = –2^x – 3. Compare and contrast the domain and range of f(x) and g(x) Describe the graphs of the functions f(x) = 2^x – 3 and g(x) = –2^x – 3. Compare and contrast the domain and range of f(x) and g(x) @Mathematics
f(x) = 2^x – 3 y-intercept=-2 horizontal asymptote: y=-3 Domain all reals, Range y ≥-3
g(x) = –2^x – 3 y-int=-2 horizontal asymptote=-3 Domain ALL REALS Range y≤-3
f(x) increases as x increases g(x) decreases as x increases
Thank you :) how did you find the range?
Imagine if \[x \to -\infty\]then \[2^x \to 0\]which leave the equations as f(x)=-3 and g(x)=-3. so they cannot go past -3.
actually I made a slight mistake since x cannot equal infinity, f(x) and g(x) cannot EQUAL 3, they can only approach it asymptotically, so the ranges should be f(x): y>-3 and g(x) y<-3
Oh ok, so 3 is like the discontinuity?
Well, a discontinuity is a point where the graph has a "hole" or a "jump". This is not the case here, since the function is continuous. The point is that making x more and more negative only APPROACHES 3, but never equals it. I presume you have not studied limits yet, but the idea will become more clear when you do.
Mhm, thanks for your help, and sorry im not to good with ranges in graphs haha.
So if the line goes on the number and goes in a certain direction, that is how you find the range?
Yeah many ranges can only be determined through Calculus, but some things to watch for are square roots and exponential functions, like \[y=\sqrt x\] has a range of \[[0,\infty)\]because if x<0 y is imaginary (In this case the domain is the same as the range. Think about why.) Or\[y=a^x\]has a range of \[(0,\infty]\]notice that 0 is not included in the range because in order to get \[y=0\] we must have\[ x=-\infty\] which we cannot do (plugging in infinity as a value is generally a no-no in basic mathematics)
I have no idea what you meant by your last question...
The range is the set of all possible values a function can take on. I'm not sure I can describe it much beyond that.
Kk well thank you for your help :)
Oh I totally get it now, I had to graph it -__- lol thank you so much
Join our real-time social learning platform and learn together with your friends!