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what is the lim x-> infinity: ((e^(1/2)/2)x)/e^(x^2/8) @MIT 18.02 Multiva…
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not sure how this would look can you use the equation editor button below the text box
\[((e ^{1/2}/2)x )/e ^{x ^{2}/8}\]
if the denominator is \[e^{\frac{x^2}{8}}\] then the limit is 0
still not sure what the numerator is though...
this?\[\frac{xe^{1/2}}{2}\]
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yeah it goes to zero because exponentially growing much faster on the bottom
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