Question

Find Derivative of .... (x^2-5x+9)^.5

Answer 1

\[(x^2-5x+9)^{1/2}\]?

Answer 2

yes

Answer 3

Im pretty positive the answer is 1/2(x2−5x+9)^1/2 x (2x-5)

Answer 4

but i want to simplify it further in order to find the critical points of the derivative so I just need help with the algebra part to simplify it down...

Answer 5

\[\frac{2x-5}{2\sqrt{x^2-5x+9}}\]

Answer 6

zero at


\[x=\frac{5}{2}\] and critical points where the denominator = 0 (which is where your original function is 0 as well.

Answer 7

actually your function is never zero, so forget that. just
\[x=\frac{5}{2}\]

Answer 8

remember the negative sign on your exponent.
\[1/2\left( x ^{2} - 5x +9\right)^{-1/2} \times \left( 2x-5\right)\]

Answer 9

\[U ^{1/2}\]
\[1/2U ^{-1/2}\]
\[1/2(x^2-5x+9)^{-1/2}(2x-5)\]

Answer 10

pretty much rewrite and solve for x

Answer 11

\[x ^{1/2} =\sqrt{x}\]
\[x ^{-1} = 1/x\]
\[x^{-1/2} = 1/\sqrt{x}\]

Answer 12

to the original poster, that's some help w/ simplifying