Find Derivative of .... (x^2-5x+9)^.5

Question

anonymous · Answer

$$(x^2-5x+9)^{1/2}$$?

anonymous · Answer

yes

anonymous · Answer

Im pretty positive the answer is 1/2(x2−5x+9)^1/2  x  (2x-5)

anonymous · Answer

but i want to simplify it further in order to find the critical points of the derivative so I just need help with the algebra part to simplify it down...

anonymous · Answer

$$\frac{2x-5}{2\sqrt{x^2-5x+9}}$$

anonymous · Answer

zero at 


$$x=\frac{5}{2}$$ and critical points where the denominator = 0 (which is where your original function is 0 as well.

anonymous · Answer

actually your function is never zero, so forget that.  just 
$$x=\frac{5}{2}$$

anonymous · Answer

remember the negative sign on your exponent.
$$1/2\left( x ^{2} - 5x +9\right)^{-1/2} \times \left( 2x-5\right)$$

anonymous · Answer

$$U ^{1/2}$$
$$1/2U ^{-1/2}$$
$$1/2(x^2-5x+9)^{-1/2}(2x-5)$$

anonymous · Answer

pretty much rewrite and solve for x

anonymous · Answer

$$x ^{1/2} =\sqrt{x}$$
$$x ^{-1} = 1/x$$
$$x^{-1/2} = 1/\sqrt{x}$$

anonymous · Answer

to the original poster, that's some help w/ simplifying