Question

Describe the nature of the roots for this equation.

3x^2+x-5=0

A. Two complex roots
B. Two real, rational roots
C. One real, double root
D. Two real, irrational roots
Describe the nature of the roots for this equation.

3x^2+x-5=0

A. Two complex roots
B. Two real, rational roots
C. One real, double root
D. Two real, irrational roots
@Mathematics

Answer 1

b^2-4ac

Answer 2

Well, you should start by using the quadratic formula, check how the delta is. A negative number under a root means there is no solution in R (so it's a complex root)... ;)

Answer 3

so a?

Answer 4

D

Answer 5

If D greater than or equal to 0 the roots are real.

If D less than the roots are not real

If D=0 the roots are equal.

If D is a perfect square, the roots are rational.

Answer 6

a = 3
b = 1
c = -5

b^2 -4ac .
1 -4(3)(-5). Doesn't look like a negative number to me :)

Answer 7

i guess nobody is trying my question :(