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Why does lim (1 + 1/x)^x when x tends to + inf, equals e?
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You know \[e ^{\ln x}\] is always equal to x. Just try doig the same thing there and you'll see what will happen.
I really don't get it, would you mind to explain a bit more? Should I do: \[\lim_{x \rightarrow \infty} e^{\ln (1+1/x)^x} \]
Perhaps by definition. Let that limit equal a value we call e.
you would still need to prove that the limit converges.
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