Question

find the value of c that makes each trinomial a perfect square. then write the trinomial as a perfect square. the equation , x^2+11x+c

Answer 1

take half of 11 and square it to get


(11/2)^2 = 121/4


This is the value that is missing from x^2+11x to make it a perfect square


So c = 121/4


and


\[\Large x^2+11x+\frac{121}{4} = \left(x+\frac{11}{2}\right)^2\]

Answer 2

thanks!

Answer 3

yw

Answer 4

so the answer would be 121/4/

Answer 5

that's the value of c, so that's the first part of the answer

Answer 6

then what would you do next?

Answer 7

you mean to factor?

Answer 8

what would be the trinomial as the perfect square?

Answer 9

the trinomial as a perfect square is


\[\Large \left(x+\frac{11}{2}\right)^2\]

Answer 10

Ohhh okay i Get it now ! (: Thanks .

Answer 11

np