need help on the attachment @MIT 18.01 Single …
if a read it right, 12/4 = 3 months per quarter; and the second quarter is from 3 to 6 months the average for the 2nd Qtr is then: S(6)-S(3) ------- ; average rate is measured by the slope between end points 6 - 3
the live preview lies .... it doesnt take into account the width of the icon, urg
\[\frac{S(6)-S(3)}{6-3}\]
Sorry for taking while to respond, but internet was off for while. I still don't get what to do next?
do you not understand how to apply amistre's answer and finish?
you can find S(6) right? it's just a good old-fashioned plug in and solve situation
the value when t=6, subtract the value when t=3 and divide the whole thing by 6-3, which is 3
the function notation S(t) means: the value of S depends on the value of "t" when "t" is replaced by a number; that indicated that t takes on that value in the equation. S(6) means; the value of the function when t=6 S(15) means;the value of the function when t=15 and so on
where did you get 15 from
I plug in 6 into the equation and got 141, and the I plug in 3 into equation and got 39. then I subtracted 141-39=102/3=34, but there no answer choice with 34
The 15 was just an hypothetical example, it is not a part of your problem. I did, however, do the problem myself and came to the same conclusion as you: 34 hm.... what's going on here? I'll have to think about it. Maybe I'll look for amistre. Maybe your paper has an error? I'll get back to you.
ok
then average is meaning something else in this context perhaps
still reads the same to me ... the average over the 2nd qtr. we got our quarters good? 1st 1-3 2nd 3-6 3rd 6-9 4th 9-12 looks good there
maybe it 4 to 6
try that: S(6) - S(4) -------- 6-4
I got 38 and that still not one of the answer choices
yeah, 38 is that one .... hmmm
its apparently using "average" in a different context than normal
maybe we have to take the derivative or anti-derivative of the function then plug the numbers in
that would make practically no sense
maybe the average from 1 to 6? derivative is the instantaneuos average at a point; not over an interval
that would be 26 which is not answer choice
you can try your derivative idea .... cant hurt :)
instantaneous average lol .... like thats a word
after of taking the derivative of the function I get 16t-2, and then plug in 6 and 1 respectively into the t variable I get 80
the derivative should be 8t-2. so sorry but we're still messing up apparently
yep your right my bad
thats not what a derivative does. you dont take an average by comparing the rates of change at 2 seperate times
the answers are so much larger than it seems they should be, something seems amiss here
well I copy down the problem right
if im going 20 miles an hour at 4pm and 75 mph at 5:30pm then my average between 4 and 5:30 is not the sum of 20 and 75, divided by 2
I don't doubt it, but somebody made a mistake somewhere, I am almost certain.
you got this online, right? they maybe made a mistake somewhere
well its an online homework called quest
the mistake is in how they worded the problem most likely; its like the said one thing but meant another
try integrating if from 3 to 6 maybe?
well "quest" seems errant as far as I can tell
let's try...
222 aint an answer :)
no it ain't
What Does Average Inventory Mean? A calculation comparing the value or number of a particular good or set of goods during two or more specified time periods. Average inventory is the median value of an inventory throughout a certain time period. A basic calculation for average inventory would be: (Current Inventory + Previous Inventory) / 2 For example, the current inventory, $10,000, is added to a previous inventory - for example, the inventory on the same day of the previous year, such as $8,000 - and divided by the two balance points, for an average of $9,000 (($10,000 + $8,000) / 2 = $9,000). http://www.investopedia.com/terms/a/average-inventory.asp#ixzz1dR3avXBX
right, which is what we did, so WHAT IS HAPPENING HERE?
I think this "quest" is quixotic ;)
try: S(4,5,6) ------- 3
add up the 4,5,6 months which is the 2ndqtr, and divide by 3
101.666666........ is not the answer
click on next and head to another problem :)
yup, I agree
ok
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