give exact and approximate solutions to three decimal place
y^2-14y+49=25

Question

mimi_x3 · Answer

y^2 - 14y +24 = 0

a = 1 , b = 14 , c = -24 

Sub it into the quadratic formula.

mimi_x3 · Answer

c=24*

mertsj · Answer

Factor;  (y-2)(y-12)=0  If the product of factors is 0, one of the factors is 0.  So y-2 = 0 or y - 12 = 0.  So y = 2 or y = 12

anonymous · Answer

how about this one anyone y^2-6y+9=81

mertsj · Answer

You really need to learn how to solve these quadratic equations.  Factor y^2 - 14y + 49.  It is a trinomial square and its factors are (y-7)^2.  So now you have (y-7)^2 = 25.  Take the square root of both sides and get y - 7 = +/-5.  Add 7 to both sides and get 12 or 2.